What is expand (3(-y+2)^2)/8 ?

The solution to expand (3(-y+2)^2)/8 is (3y^2)/8-(3y)/2+3/2

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expand (3(-y+2)^2)/8

expand

\frac{3 ( - y + 2 ) ^{2}}{8}

\frac{3 y ^{2}}{8} - \frac{3 y}{2} + \frac{3}{2}

Solution steps

\frac{3 ( - y + 2 ) ^{2}}{8}

(- y + 2)^{2} = y^{2} - 4 y + 4

= \frac{3 ( y ^{2} - 4 y + 4 )}{8}

Expand

3 (y^{2} - 4 y + 4) : 3 y^{2} - 12 y + 12

= \frac{3 y ^{2} - 12 y + 12}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 y ^{2} - 12 y + 12}{8} = \frac{3 y ^{2}}{8} - \frac{12 y}{8} + \frac{12}{8}

= \frac{3 y ^{2}}{8} - \frac{12 y}{8} + \frac{12}{8}

Cancel

\frac{12 y}{8} : \frac{3 y}{2}

= \frac{3 y ^{2}}{8} - \frac{3 y}{2} + \frac{12}{8}

Cancel

\frac{12}{8} : \frac{3}{2}

= \frac{3 y ^{2}}{8} - \frac{3 y}{2} + \frac{3}{2}

\frac{( a + b ) ^{2}}{b}

\frac{x + 1}{( x - 2 ) ^{2} ( x ^{2} + 2 )}

(2 x - Q x) d x

\frac{( x ^{2} + 1 ) ( x ^{3} - 1 )}{2 x}

- 3 x - (7 x + 4 = - 4 (3 x + 1))

What is expand (3(-y+2)^2)/8 ?
The solution to expand (3(-y+2)^2)/8 is (3y^2)/8-(3y)/2+3/2