What is expand 3(x+Δx)^2-9(x+Δx) ?

The solution to expand 3(x+Δx)^2-9(x+Δx) is 3x^2+6Δx^2+3Δ^2x^2-9x-9Δx

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expand 3(x+Δx)^2-9(x+Δx)

expand

3 (x + Δ x)^{2} - 9 (x + Δ x)

3 x^{2} + 6Δ x^{2} + 3 Δ^{2} x^{2} - 9 x - 9Δ x

Solution steps

3 (x + Δ x)^{2} - 9 (x + Δ x)

Expand

- 9 (x + Δ x) : - 9 x - 9Δ x

= 3 (x + Δ x)^{2} - 9 x - 9Δ x

Simplify

3 (x + Δ x)^{2} - 9 x - 9Δ x : 3 x^{2} + 6Δ x^{2} + 3 Δ^{2} x^{2} - 9 x - 9Δ x

= 3 x^{2} + 6Δ x^{2} + 3 Δ^{2} x^{2} - 9 x - 9Δ x

(\frac{π}{2} + 2) 16

\frac{4 ( x - 5 ) ( x + 4 )}{x + 5}

\frac{d}{d x} (a sin (b (x - c))) + d

\frac{2 b ^{3}}{3 ( b + 4 ) ^{2}}

a^{2} + a - ab - b - a - 1

What is expand 3(x+Δx)^2-9(x+Δx) ?
The solution to expand 3(x+Δx)^2-9(x+Δx) is 3x^2+6Δx^2+3Δ^2x^2-9x-9Δx