What is expand ((1-γ^2)x+γ^2vt)/(γv) ?

The solution to expand ((1-γ^2)x+γ^2vt)/(γv) is x/(γv)-(γx)/v+γt

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expand ((1-γ^2)x+γ^2vt)/(γv)

expand

\frac{( 1 - γ ^{2} ) x + γ ^{2} v t}{γ v}

\frac{x}{γ v} - \frac{γ x}{v} + γ t

Solution steps

\frac{( 1 - γ ^{2} ) x + γ ^{2} v t}{γ v}

Expand

(1 - γ^{2}) x + γ^{2} v t : x - γ^{2} x + γ^{2} v t

= \frac{x - γ ^{2} x + γ ^{2} v t}{γ v}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x - γ ^{2} x + γ ^{2} v t}{γ v} = \frac{x}{γ v} - \frac{γ ^{2} x}{γ v} + \frac{γ ^{2} v t}{γ v}

= \frac{x}{γ v} - \frac{γ ^{2} x}{γ v} + \frac{γ ^{2} v t}{γ v}

Cancel

\frac{γ ^{2} x}{γ v} : \frac{γ x}{v}

= \frac{x}{γ v} - \frac{γ x}{v} + \frac{γ ^{2} v t}{γ v}

Cancel

\frac{γ ^{2} v t}{γ v} : γ t

= \frac{x}{γ v} - \frac{γ x}{v} + γ t

- 1 y (- 2, - 2)

\frac{1 + x ( x - 2 )}{x - 2}

(z - 1) \cdot (z - \frac{1}{e ^{3}})

\frac{- 3 ( x + y ) ^{2} + 2 ( x + y ) + 1}{y}

g (- 2 = 5 - (2)^{2})

What is expand ((1-γ^2)x+γ^2vt)/(γv) ?
The solution to expand ((1-γ^2)x+γ^2vt)/(γv) is x/(γv)-(γx)/v+γt