What is expand ((3-3y)/2)^2 ?

The solution to expand ((3-3y)/2)^2 is (9y^2)/4-(9y)/2+9/4

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expand ((3-3y)/2)^2

expand

(\frac{3 - 3 y}{2})^{2}

\frac{9 y ^{2}}{4} - \frac{9 y}{2} + \frac{9}{4}

Solution steps

(\frac{3 - 3 y}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 - 3 y ) ^{2}}{2 ^{2}}

(3 - 3 y)^{2} = 9 - 18 y + 9 y^{2}

= \frac{9 - 18 y + 9 y ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{9 - 18 y + 9 y ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 18 y + 9 y ^{2}}{4} = \frac{9}{4} - \frac{18 y}{4} + \frac{9 y ^{2}}{4}

= \frac{9}{4} - \frac{18 y}{4} + \frac{9 y ^{2}}{4}

Cancel

\frac{18 y}{4} : \frac{9 y}{2}

= \frac{9}{4} - \frac{9 y}{2} + \frac{9 y ^{2}}{4}

Rewrite in standard form

= \frac{9 y ^{2}}{4} - \frac{9 y}{2} + \frac{9}{4}

(2 a + 5 b) e^{5}

\frac{63}{( x - 2 ) ( x ^{2} + 5 )}

(2 + e^{x})^{4}

2 + (\frac{25}{( x + 1 ) ^{2}})

\frac{( s - 1 ) s}{s ( s - 1 ) ^{2} - 1}

What is expand ((3-3y)/2)^2 ?
The solution to expand ((3-3y)/2)^2 is (9y^2)/4-(9y)/2+9/4