What is expand (3(k+10))/((2x+1)(x-3)) ?

The solution to expand (3(k+10))/((2x+1)(x-3)) is (3k+30)/(2x^2-5x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3(k+10))/((2x+1)(x-3))

expand

\frac{3 ( k + 10 )}{( 2 x + 1 ) ( x - 3 )}

\frac{3 k + 30}{2 x ^{2} - 5 x - 3}

Solution steps

\frac{3 ( k + 10 )}{( 2 x + 1 ) ( x - 3 )}

Expand

(2 x + 1) (x - 3) : 2 x^{2} - 5 x - 3

= \frac{3 ( k + 10 )}{2 x ^{2} - 5 x - 3}

Expand

3 (k + 10) : 3 k + 30

= \frac{3 k + 30}{2 x ^{2} - 5 x - 3}

e^{4 y - x^{2} - y^{2}} (- 2 y + 4)

\frac{z ( x - y )}{x + y}

+ \frac{x ( - x + 3 ) ^{2}}{6}

(1.01)^{3}

\frac{y ( 2 x - 2 y )}{( - 1 + x y ^{2} )}

What is expand (3(k+10))/((2x+1)(x-3)) ?
The solution to expand (3(k+10))/((2x+1)(x-3)) is (3k+30)/(2x^2-5x-3)