What is expand (x-1)/((x-3)(x+4)) ?

The solution to expand (x-1)/((x-3)(x+4)) is (x-1)/(x^2+x-12)

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expand (x-1)/((x-3)(x+4))

expand

\frac{x - 1}{( x - 3 ) ( x + 4 )}

\frac{x - 1}{x ^{2} + x - 12}

Solution steps

\frac{x - 1}{( x - 3 ) ( x + 4 )}

Expand

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{x - 1}{x ^{2} + x - 12}

\frac{1}{( b - a ) ( a - x )}

(- 4, - 3) y (8, - 9)

64 (10 k - 10 m + 1)^{2}

76 - 2

\frac{f ( x + h ) - 5 x - 6}{h}

What is expand (x-1)/((x-3)(x+4)) ?
The solution to expand (x-1)/((x-3)(x+4)) is (x-1)/(x^2+x-12)