What is expand ν(1,-2,3)P(a,b,c) ?

The solution to expand ν(1,-2,3)P(a,b,c) is 1*νP(,,abc),-2νP(,,abc),3

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expand ν(1,-2,3)P(a,b,c)

expand

ν (1, - 2, 3) P (a, b, c)

1 \cdot ν P (,, ab c), - 2 ν P (,, ab c), 3

Solution steps

ν (1, - 2, 3) P (a, b, c)

= (1, - 2 \cdot 3,) ν P (,, ab c)

Apply the distributive law:

a (b - c) = ab - a c

a = ν P (a, b, c), b = 1,, c = 2, 3

= ν P (a, b, c) \cdot 1, - ν P (a, b, c) \cdot 2, 3

= 1 \cdot ν P (,, ab c), - 2 ν P (,, ab c), 3

(240 - e^{0.05 q}) \cdot q

\frac{1}{( 1 + h ) ^{2}}

\frac{y}{( y - 3 x ^{2} ) ( y - x ^{2} )}

\frac{1 + 2 x + x ^{2} - q ( 1 - x )}{1 + x}

9 (- 5 x - 2 y = - 6)

What is expand ν(1,-2,3)P(a,b,c) ?
The solution to expand ν(1,-2,3)P(a,b,c) is 1*νP(,,abc),-2νP(,,abc),3