What is expand 3-x-((3-x)^3)/3 ?

The solution to expand 3-x-((3-x)^3)/3 is (x^3)/3-3x^2+8x-6

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expand 3-x-((3-x)^3)/3

expand

3 - x - \frac{( 3 - x ) ^{3}}{3}

\frac{x ^{3}}{3} - 3 x^{2} + 8 x - 6

Solution steps

3 - x - \frac{( 3 - x ) ^{3}}{3}

(3 - x)^{3} = 27 - 27 x + 9 x^{2} - x^{3}

= 3 - x - \frac{- x ^{3} + 9 x ^{2} - 27 x + 27}{3}

Combine the fractions

- \frac{- x ^{3} + 9 x ^{2} - 27 x + 27}{3} - x : \frac{x ^{3} - 9 x ^{2} + 24 x - 27}{3}

= \frac{x ^{3} - 9 x ^{2} + 24 x - 27}{3} + 3

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 9 x ^{2} + 24 x - 27}{3} = \frac{x ^{3}}{3} - \frac{9 x ^{2}}{3} + \frac{24 x}{3} - \frac{27}{3}

= \frac{x ^{3}}{3} - \frac{9 x ^{2}}{3} + \frac{24 x}{3} - \frac{27}{3} + 3

Divide the numbers:

\frac{9}{3} = 3

= \frac{x ^{3}}{3} - 3 x^{2} + \frac{24 x}{3} - \frac{27}{3} + 3

Divide the numbers:

\frac{24}{3} = 8

= \frac{x ^{3}}{3} - 3 x^{2} + 8 x - \frac{27}{3} + 3

Divide the numbers:

\frac{27}{3} = 9

= \frac{x ^{3}}{3} - 3 x^{2} + 8 x - 9 + 3

Add/Subtract the numbers:

- 9 + 3 = - 6

= \frac{x ^{3}}{3} - 3 x^{2} + 8 x - 6

3 (x + Δ x)^{4} + (2 (x + Δ x) - 1)^{2}

\frac{2 g ( h - g )}{g h - j}

- 20 (8 e - 20)

\frac{10 ( 7 - 1 )}{7}

- \frac{2 ( 45 + 8885 )}{49}

What is expand 3-x-((3-x)^3)/3 ?
The solution to expand 3-x-((3-x)^3)/3 is (x^3)/3-3x^2+8x-6