What is (4-x^{2\circ}x-2)(x) ?

The solution to (4-x^{2\circ}x-2)(x) is x(-x^{2\circ+1}+2)

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simplify (4-x^{2\circ}x-2)(x)

simplify

(4 - x^{2 \circ} x - 2) (x)

x (- x^{2 \circ+ 1} + 2)

Solution steps

(4 - x^{2 \circ} x - 2) (x)

Remove parentheses:

(a) = a

= (4 - x^{2 \circ} x - 2) x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2 \circ} x = x^{2 \circ + 1}

= x (- x^{2 \circ + 1} + 4 - 2)

Simplify

4 - x^{2 \circ + 1} - 2 : - x^{2 \circ + 1} + 2

= x (- x^{2 \circ + 1} + 2)

(2.5569300000000 \dots + 1.0195000000000 \dots ln (x))^{2}

(10 x + 7 y + 3 z = 7,) (10 x + 7 x + 3 x = 10)

\frac{( 1 + j ) ^{9}}{( 1 - j ) ^{7}}

\frac{D w}{( s ^{2} + w ^{2} ) ( s + a )}

lo g_{10} (x) 5 zy 5

What is (4-x^{2\circ}x-2)(x) ?
The solution to (4-x^{2\circ}x-2)(x) is x(-x^{2\circ+1}+2)