What is expand-(3y^2(-3y+3)^2)/2 ?

The solution to expand-(3y^2(-3y+3)^2)/2 is -(27y^4)/2+27y^3-(27y^2)/2

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expand-(3y^2(-3y+3)^2)/2

expand

- \frac{3 y ^{2} ( - 3 y + 3 ) ^{2}}{2}

- \frac{27 y ^{4}}{2} + 27 y^{3} - \frac{27 y ^{2}}{2}

Solution steps

- \frac{3 y ^{2} ( - 3 y + 3 ) ^{2}}{2}

(- 3 y + 3)^{2} = 9 y^{2} - 18 y + 9

= - \frac{3 y ^{2} ( 9 y ^{2} - 18 y + 9 )}{2}

Expand

3 y^{2} (9 y^{2} - 18 y + 9) : 27 y^{4} - 54 y^{3} + 27 y^{2}

= - \frac{27 y ^{4} - 54 y ^{3} + 27 y ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 y ^{4} - 54 y ^{3} + 27 y ^{2}}{2} = - (\frac{27 y ^{4}}{2}) - (- \frac{54 y ^{3}}{2}) - (\frac{27 y ^{2}}{2})

= - (\frac{27 y ^{4}}{2}) - (- \frac{54 y ^{3}}{2}) - (\frac{27 y ^{2}}{2})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{27 y ^{4}}{2} + \frac{54 y ^{3}}{2} - \frac{27 y ^{2}}{2}

Divide the numbers:

\frac{54}{2} = 27

= - \frac{27 y ^{4}}{2} + 27 y^{3} - \frac{27 y ^{2}}{2}

P^{1} (2, - 5)

f (s, y) (s = 5 - 3 y)

(t + 2 y) + (2 t + 1) y^{'} (t)

\frac{9}{( 1 + x ) ^{2}}

10 x^{3} + 5 5^{2} + 25 x

What is expand-(3y^2(-3y+3)^2)/2 ?
The solution to expand-(3y^2(-3y+3)^2)/2 is -(27y^4)/2+27y^3-(27y^2)/2