What is expand (x(x^2+3x-6))/3 ?

The solution to expand (x(x^2+3x-6))/3 is (x^3)/3+x^2-2x

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expand (x(x^2+3x-6))/3

expand

\frac{x ( x ^{2} + 3 x - 6 )}{3}

\frac{x ^{3}}{3} + x^{2} - 2 x

Solution steps

\frac{x ( x ^{2} + 3 x - 6 )}{3}

Expand

x (x^{2} + 3 x - 6) : x^{3} + 3 x^{2} - 6 x

= \frac{x ^{3} + 3 x ^{2} - 6 x}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 3 x ^{2} - 6 x}{3} = \frac{x ^{3}}{3} + \frac{3 x ^{2}}{3} - \frac{6 x}{3}

= \frac{x ^{3}}{3} + \frac{3 x ^{2}}{3} - \frac{6 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= \frac{x ^{3}}{3} + x^{2} - \frac{6 x}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{x ^{3}}{3} + x^{2} - 2 x

x - 2 (x + 1) d x

A (4, - 2) B (- 3, - 1)

4 (4 a = 5 b + 13)

\frac{( 3 x + 2 ) ^{6}}{9}

\frac{x ( 3 x ^{2} - 1 )}{1 - x ^{4}}

What is expand (x(x^2+3x-6))/3 ?
The solution to expand (x(x^2+3x-6))/3 is (x^3)/3+x^2-2x