What is expand cos(3t)sin(2t)e^{4t}U(t-pi) ?

The solution to expand cos(3t)sin(2t)e^{4t}U(t-pi) is e^{4t}tUcos(3t)sin(2t)-pie^{4t}Ucos(3t)sin(2t)

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expand cos(3t)sin(2t)e^{4t}U(t-pi)

expand

cos (3 t) sin (2 t) e^{4 t} U (t - π)

e^{4 t} t U cos (3 t) sin (2 t) - π e^{4 t} U cos (3 t) sin (2 t)

Solution steps

cos (3 t) sin (2 t) e^{4 t} U (t - π)

= e^{4 t} U cos (3 t) sin (2 t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = cos (3 t) sin (2 t) e^{4 t} U, b = t, c = π

= cos (3 t) sin (2 t) e^{4 t} U t - cos (3 t) sin (2 t) e^{4 t} U π

= e^{4 t} t U cos (3 t) sin (2 t) - π e^{4 t} U cos (3 t) sin (2 t)

\frac{( x + 1 ) ^{2}}{49}

\frac{x + 2}{( x + 2 ) x ^{2} - 2 x + 4}

\frac{a \cdot s + 1}{( s + 1 ) ^{2}}

(2 e^{x} + 1 - e^{- x}) \cdot e^{x}

a cot (\frac{x y}{( x + 2 ) ^{2}})

What is expand cos(3t)sin(2t)e^{4t}U(t-pi) ?
The solution to expand cos(3t)sin(2t)e^{4t}U(t-pi) is e^{4t}tUcos(3t)sin(2t)-pie^{4t}Ucos(3t)sin(2t)