What is expand (x+3)(x+1)(3x+!) ?

The solution to expand (x+3)(x+1)(3x+!) is 3!x^3+12!x^2+9!x

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expand (x+3)(x+1)(3x+!)

expand

(x + 3) (x + 1) (3 x +!)

3! x^{3} + 12! x^{2} + 9! x

Solution steps

(x + 3) (x + 1) (3 x +!)

= (x + 3) (x + 1) (3 +! x)

Expand

(x + 3) (x + 1) : x^{2} + 4 x + 3

= (3 x +!) (x^{2} + 4 x + 3)

Expand

(3 x +!) (x^{2} + 4 x + 3) : 3! x^{3} + 12! x^{2} + 9! x

= 3! x^{3} + 12! x^{2} + 9! x

- 3 (1 - 7 n = 9) (- 6 + 8 n)

\frac{36}{4}

(4, - 4, 4) x (- 3, - 7, 3)

2 b^{2} + 4 - 2 b^{2} - 4

\frac{1 - e ^{- T s}}{( 10 s + 1 ) s ^{2}}

What is expand (x+3)(x+1)(3x+!) ?
The solution to expand (x+3)(x+1)(3x+!) is 3!x^3+12!x^2+9!x