What is expand 2((3r-s)=5(s+2t)-4(2t+s)) ?

The solution to expand 2((3r-s)=5(s+2t)-4(2t+s)) is 6r-2s=-3s-6t

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expand 2((3r-s)=5(s+2t)-4(2t+s))

expand

2 ((3 r - s) = 5 (s + 2 t) - 4 (2 t + s))

6 r - 2 s = - 3 s - 6 t

Solution steps

2 ((3 r - s) = 5 (s + 2 t) - 4 (2 t + s))

= 2 (5 = (3 r - s) (s + 2 t) - 4 (2 t + s))

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = (3 r - s) = 5 (s + 2 t), c = 4 (2 t + s)

2 (3 r - s) = 5 (s + 2 t) - 2 \cdot 4 (2 t + s)

Simplify

2 (3 r - s) = 5 (s + 2 t) - 2 \cdot 4 (2 t + s) : 6 r - 2 s = - 3 s - 6 t

6 r - 2 s = - 3 s - 6 t

1 3^{(9 x + 6)}

\frac{( 2 - t ^{5} ) ^{3}}{8 t ^{6}}

\frac{x ( x - 3 )}{( x - 1 ) ( x - 5 )}

(y^{1} = 2, - x^{2}) (y_{2} = - x)

\frac{( 3 + X ) ( 3 - X )}{X ^{2}}

What is expand 2((3r-s)=5(s+2t)-4(2t+s)) ?
The solution to expand 2((3r-s)=5(s+2t)-4(2t+s)) is 6r-2s=-3s-6t