What is expand (1+4e^{-4t})^2 ?

The solution to expand (1+4e^{-4t})^2 is 1+8e^{-4t}+16e^{-8t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (1+4e^{-4t})^2

expand

(1 + 4 e^{- 4 t})^{2}

1 + 8 e^{- 4 t} + 16 e^{- 8 t}

Solution steps

(1 + 4 e^{- 4 t})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 1, b = 4 e^{- 4 t}

= 1^{2} + 2 \cdot 1 \cdot 4 e^{- 4 t} + (4 e^{- 4 t})^{2}

Simplify

1^{2} + 2 \cdot 1 \cdot 4 e^{- 4 t} + (4 e^{- 4 t})^{2} : 1 + 8 e^{- 4 t} + 16 e^{- 8 t}

= 1 + 8 e^{- 4 t} + 16 e^{- 8 t}

(i + i)^{2}

- 2 (e^{3 x} + 10 e^{2 x})

(8 - 4 e^{- x})^{2}

\frac{4 x + 32}{( x + 4 ) ^{2}}

9 (5 x - 2 y = 6)

What is expand (1+4e^{-4t})^2 ?
The solution to expand (1+4e^{-4t})^2 is 1+8e^{-4t}+16e^{-8t}