What is expand (-2x)^{\circ-1}(x+y) ?

The solution to expand (-2x)^{\circ-1}(x+y) is x(-2x)^{\circ-1}+y(-2x)^{\circ-1}

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expand (-2x)^{\circ-1}(x+y)

expand

(- 2 x)^{\circ - 1} (x + y)

x (- 2 x)^{\circ- 1} + y (- 2 x)^{\circ- 1}

Solution steps

(- 2 x)^{\circ - 1} (x + y)

= (x + y) (- 2 x)^{\circ - 1}

Apply the distributive law:

a (b + c) = ab + a c

a = (- 2 x)^{\circ - 1}, b = x, c = y

= (- 2 x)^{\circ - 1} x + (- 2 x)^{\circ - 1} y

= x (- 2 x)^{\circ - 1} + y (- 2 x)^{\circ - 1}

\frac{4}{( 3 - x ) ^{3}}

\frac{a + b ( a + b y )}{a - b ( a - b y )}

\frac{b ( a - 1 )}{1 + b ^{2} a}

(5 x - x^{2} - 6) d y - (1 - x) d x

(x + 3 y) d x - (3 x + y) d y

What is expand (-2x)^{\circ-1}(x+y) ?
The solution to expand (-2x)^{\circ-1}(x+y) is x(-2x)^{\circ-1}+y(-2x)^{\circ-1}