What are the solutions to the equation 2k(k+15)=15 ?

The solutions to the equation 2k(k+15)=15 are k=(-15+sqrt(255))/2 ,k=-(15+sqrt(255))/2

Find the zeros of 2k(k+15)=15

The zeros of 2k(k+15)=15 are k=(-15+sqrt(255))/2 ,k=-(15+sqrt(255))/2

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2 k (k + 15) = 15

k = \frac{- 15 + 255}{2}, k = - \frac{15 + 255}{2}

Decimal Notation

k = 0.48435 \dots, k = - 15.48435 \dots

Solution steps

2 k (k + 15) = 15

Expand

2 k (k + 15) : 2 k^{2} + 30 k

2 k^{2} + 30 k = 15

Move

15

to the left side

2 k^{2} + 30 k - 15 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

3 0^{2} - 4 \cdot 2 (- 15) = 2255

k_{1, 2} = \frac{- 30 \pm 2 255}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 30 + 2 255}{2 \cdot 2}, k_{2} = \frac{- 30 - 2 255}{2 \cdot 2}

k = \frac{- 30 + 2 255}{2 \cdot 2} : \frac{- 15 + 255}{2}

k = \frac{- 30 - 2 255}{2 \cdot 2} : - \frac{15 + 255}{2}

The solutions to the quadratic equation are:

k = \frac{- 15 + 255}{2}, k = - \frac{15 + 255}{2}

X^{3} - 8

f = 4 (- 2) - 3

\frac{1}{2} \cdot 11

7 (- 2) - 2 (5) = 13

a^{2} - 5 a - 24

What are the solutions to the equation 2k(k+15)=15 ?
The solutions to the equation 2k(k+15)=15 are k=(-15+sqrt(255))/2 ,k=-(15+sqrt(255))/2
Find the zeros of 2k(k+15)=15
The zeros of 2k(k+15)=15 are k=(-15+sqrt(255))/2 ,k=-(15+sqrt(255))/2