What is expand 1/(1+e^{-(α(β-θ)))} ?

The solution to expand 1/(1+e^{-(α(β-θ)))} is 1/(1+e^{-αβ+αθ)}

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expand 1/(1+e^{-(α(β-θ)))}

expand

\frac{1}{1 + e ^{- (α (β - θ))}}

\frac{1}{1 + e ^{- α β + α θ}}

Solution steps

\frac{1}{1 + e ^{- (α (β - θ))}}

Remove parentheses:

(a) = a

= \frac{1}{1 + e ^{- α (β - θ)}}

Expand

- α (β - θ) : - α β + α θ

= \frac{1}{1 + e ^{α θ - α β}}

(ln (t) + 1)^{3}

\frac{x ^{2} - 7}{( x + 4 ) ( x - 7 )}

(x \circ x + 8) (x)

(x^{2} sin (x) + 4 y) d y

(4, - 1, 0) (8 x - 4 y + z + 9 = 0)

What is expand 1/(1+e^{-(α(β-θ)))} ?
The solution to expand 1/(1+e^{-(α(β-θ)))} is 1/(1+e^{-αβ+αθ)}