What is expand (3(x+1)(x-4))/(x(3x-13)) ?

The solution to expand (3(x+1)(x-4))/(x(3x-13)) is (3x^2-9x-12)/(3x^2-13x)

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expand (3(x+1)(x-4))/(x(3x-13))

expand

\frac{3 ( x + 1 ) ( x - 4 )}{x ( 3 x - 13 )}

\frac{3 x ^{2} - 9 x - 12}{3 x ^{2} - 13 x}

Solution steps

\frac{3 ( x + 1 ) ( x - 4 )}{x ( 3 x - 13 )}

Expand

x (3 x - 13) : 3 x^{2} - 13 x

= \frac{3 ( x + 1 ) ( x - 4 )}{3 x ^{2} - 13 x}

Expand

3 (x + 1) (x - 4) : 3 x^{2} - 9 x - 12

= \frac{3 x ^{2} - 9 x - 12}{3 x ^{2} - 13 x}

\frac{1}{( s + 3 ) ( s - 2 )}

x (y + y^{'} (x))

\frac{a + 7}{( a - 1 ) ( a - 2 ) ( a + 1 )}

\frac{- 3}{4} (- 16 v + 4 = - 111)

\frac{w ^{- 4}}{z ^{- 9}}

What is expand (3(x+1)(x-4))/(x(3x-13)) ?
The solution to expand (3(x+1)(x-4))/(x(3x-13)) is (3x^2-9x-12)/(3x^2-13x)