What is expand ((2x-1)(3x+5))/2 ?

The solution to expand ((2x-1)(3x+5))/2 is 3x^2+(7x)/2-5/2

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expand ((2x-1)(3x+5))/2

expand

\frac{( 2 x - 1 ) ( 3 x + 5 )}{2}

3 x^{2} + \frac{7 x}{2} - \frac{5}{2}

Solution steps

\frac{( 2 x - 1 ) ( 3 x + 5 )}{2}

Expand

(2 x - 1) (3 x + 5) : 6 x^{2} + 7 x - 5

= \frac{6 x ^{2} + 7 x - 5}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 7 x - 5}{2} = \frac{6 x ^{2}}{2} + \frac{7 x}{2} - \frac{5}{2}

= \frac{6 x ^{2}}{2} + \frac{7 x}{2} - \frac{5}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 x^{2} + \frac{7 x}{2} - \frac{5}{2}

\frac{( 1 + i ) ^{5}}{( 2 + 3 i ) ^{5}}

\frac{d}{d y} ((x) (1 - x e^{- x}))

(x, y) \Rightarrow (x - 5, y - 3)

arcsin (- 8 (x + c))

\frac{8 ( 3 x - 7 )}{5}

What is expand ((2x-1)(3x+5))/2 ?
The solution to expand ((2x-1)(3x+5))/2 is 3x^2+(7x)/2-5/2