What is expand f/((2-2f)^2(3-f)) ?

The solution to expand f/((2-2f)^2(3-f)) is f/(12-28f+20f^2-4f^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand f/((2-2f)^2(3-f))

expand

\frac{f}{( 2 - 2 f ) ^{2} ( 3 - f )}

\frac{f}{12 - 28 f + 20 f ^{2} - 4 f ^{3}}

Solution steps

\frac{f}{( 2 - 2 f ) ^{2} ( 3 - f )}

(2 - 2 f)^{2} = 4 - 8 f + 4 f^{2}

= \frac{f}{( 4 f ^{2} - 8 f + 4 ) ( - f + 3 )}

Expand

(4 - 8 f + 4 f^{2}) (3 - f) : 12 - 28 f + 20 f^{2} - 4 f^{3}

= \frac{f}{12 - 28 f + 20 f ^{2} - 4 f ^{3}}

\frac{6}{s ^{4} ( s ^{2} + 1 )}

\frac{4}{( x - 4 ) ^{3}}

\frac{h ( h + 6 ) + 12}{h}

\frac{12 t ^{2}}{( 1 + 0.3 t ) ^{2}}

\frac{f ( 4 x + h ) - 4 x}{h}

What is expand f/((2-2f)^2(3-f)) ?
The solution to expand f/((2-2f)^2(3-f)) is f/(12-28f+20f^2-4f^3)