What is expand 3(4e^{2x}+e^{3x}) ?

The solution to expand 3(4e^{2x}+e^{3x}) is 12e^{2x}+3e^{3x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3(4e^{2x}+e^{3x})

expand

3 (4 e^{2 x} + e^{3 x})

12 e^{2 x} + 3 e^{3 x}

Solution steps

3 (4 e^{2 x} + e^{3 x})

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = 4 e^{2 x}, c = e^{3 x}

= 3 \cdot 4 e^{2 x} + 3 e^{3 x}

Multiply the numbers:

3 \cdot 4 = 12

= 12 e^{2 x} + 3 e^{3 x}

\frac{1}{s ^{2} ( s ^{2} + 2 s + 1 )}

3 a (a^{2} - 2 a = 4)

\frac{n ( n - 2 ) ( 2 n + 7 )}{6}

\frac{3 ( 5 - 3 y )}{2}

(- 4 x + 3 y = 2,) (5 x - 4 y = 1,) (3 x + z = 0)

What is expand 3(4e^{2x}+e^{3x}) ?
The solution to expand 3(4e^{2x}+e^{3x}) is 12e^{2x}+3e^{3x}