What is expand ((e^{8x}-e^{-8x}))^2 ?

The solution to expand ((e^{8x}-e^{-8x}))^2 is e^{16x}-2+e^{-16x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((e^{8x}-e^{-8x}))^2

expand

((e^{8 x} - e^{- 8 x}))^{2}

e^{16 x} - 2 + e^{- 16 x}

Solution steps

(e^{8 x} - e^{- 8 x})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{8 x}, b = e^{- 8 x}

= (e^{8 x})^{2} - 2 e^{8 x} e^{- 8 x} + (e^{- 8 x})^{2}

Simplify

(e^{8 x})^{2} - 2 e^{8 x} e^{- 8 x} + (e^{- 8 x})^{2} : e^{16 x} - 2 + e^{- 16 x}

= e^{16 x} - 2 + e^{- 16 x}

in t er sec (a) (x - 1)^{2} - 4

\frac{z}{( z - a ) ( z - 1 )}

\frac{( - 8 X + A ) ^{2}}{16}

- \frac{2 ( 4 a ^{2} b ^{2} + 3 )}{b}

\frac{( 2 x - 4 ) ^{4}}{81}

What is expand ((e^{8x}-e^{-8x}))^2 ?
The solution to expand ((e^{8x}-e^{-8x}))^2 is e^{16x}-2+e^{-16x}