What is expand ((2x+3)(3-x))/((2x+1)^2) ?

The solution to expand ((2x+3)(3-x))/((2x+1)^2) is (-2x^2+3x+9)/(4x^2+4x+1)

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expand ((2x+3)(3-x))/((2x+1)^2)

expand

\frac{( 2 x + 3 ) ( 3 - x )}{( 2 x + 1 ) ^{2}}

\frac{- 2 x ^{2} + 3 x + 9}{4 x ^{2} + 4 x + 1}

Solution steps

\frac{( 2 x + 3 ) ( 3 - x )}{( 2 x + 1 ) ^{2}}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= \frac{( 2 x + 3 ) ( - x + 3 )}{4 x ^{2} + 4 x + 1}

Expand

(2 x + 3) (3 - x) : - 2 x^{2} + 3 x + 9

= \frac{- 2 x ^{2} + 3 x + 9}{4 x ^{2} + 4 x + 1}

\frac{1}{x} sec (x)

(x^{2} + 5 x) cos (x) d x

(3 x - 5) \circ

\frac{2}{x ^{2} ( x + 2 )}

\frac{( x + 3 ) ( x + 2 )}{10}

What is expand ((2x+3)(3-x))/((2x+1)^2) ?
The solution to expand ((2x+3)(3-x))/((2x+1)^2) is (-2x^2+3x+9)/(4x^2+4x+1)