What is expand ((2x-3y)^2)/2 ?

The solution to expand ((2x-3y)^2)/2 is 2x^2-6xy+(9y^2)/2

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expand ((2x-3y)^2)/2

expand

\frac{( 2 x - 3 y ) ^{2}}{2}

2 x^{2} - 6 x y + \frac{9 y ^{2}}{2}

Solution steps

\frac{( 2 x - 3 y ) ^{2}}{2}

(2 x - 3 y)^{2} = 4 x^{2} - 12 x y + 9 y^{2}

= \frac{4 x ^{2} - 12 x y + 9 y ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 12 x y + 9 y ^{2}}{2} = \frac{4 x ^{2}}{2} - \frac{12 x y}{2} + \frac{9 y ^{2}}{2}

= \frac{4 x ^{2}}{2} - \frac{12 x y}{2} + \frac{9 y ^{2}}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 x^{2} - \frac{12 x y}{2} + \frac{9 y ^{2}}{2}

Divide the numbers:

\frac{12}{2} = 6

= 2 x^{2} - 6 x y + \frac{9 y ^{2}}{2}

\frac{( b ( b - 1 ) - 2 )}{2 ( - 1 + b ^{2} )}

- (1 - e) D

δ (a_{0} - a_{1})

\frac{1 + ( - 2 ) ^{x}}{x}

2 (n - 3 = 4 n + 1)

What is expand ((2x-3y)^2)/2 ?
The solution to expand ((2x-3y)^2)/2 is 2x^2-6xy+(9y^2)/2