What is expand (7x-6)/((3x-1)(2x-1)) ?

The solution to expand (7x-6)/((3x-1)(2x-1)) is (7x-6)/(6x^2-5x+1)

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expand (7x-6)/((3x-1)(2x-1))

expand

\frac{7 x - 6}{( 3 x - 1 ) ( 2 x - 1 )}

\frac{7 x - 6}{6 x ^{2} - 5 x + 1}

Solution steps

\frac{7 x - 6}{( 3 x - 1 ) ( 2 x - 1 )}

Expand

(3 x - 1) (2 x - 1) : 6 x^{2} - 5 x + 1

= \frac{7 x - 6}{6 x ^{2} - 5 x + 1}

(1 + 2 x + x^{2})^{6}

(x - 2) 35 6^{^{'}}

ln (a x + b) \cdot 2 x \cdot (a x + b)

(4 x + 7 y = 3, 7) (3 x - y = 16)

[x (x + 1)]^{2}

What is expand (7x-6)/((3x-1)(2x-1)) ?
The solution to expand (7x-6)/((3x-1)(2x-1)) is (7x-6)/(6x^2-5x+1)