What is expand e^{2x}(sin(2x)+cos(3x)) ?

The solution to expand e^{2x}(sin(2x)+cos(3x)) is e^{2x}sin(2x)+e^{2x}cos(3x)

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expand e^{2x}(sin(2x)+cos(3x))

expand

e^{2 x} (sin (2 x) + cos (3 x))

e^{2 x} sin (2 x) + e^{2 x} cos (3 x)

Solution steps

e^{2 x} (sin (2 x) + cos (3 x))

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x}, b = sin (2 x), c = cos (3 x)

= e^{2 x} sin (2 x) + e^{2 x} cos (3 x)

cos (\frac{( 2 x + 1 ) π}{2})

\frac{2}{( s - 1 ) ^{2} ( s - 3 )}

\frac{n ! ( n + 2 )}{( n + 1 )}

\frac{( x ( x - 10 ) )}{x + 13}

x - 6 \cdot 7 x^{2}

What is expand e^{2x}(sin(2x)+cos(3x)) ?
The solution to expand e^{2x}(sin(2x)+cos(3x)) is e^{2x}sin(2x)+e^{2x}cos(3x)