What is expand ((5x-1)(2x+1))/(10) ?

The solution to expand ((5x-1)(2x+1))/(10) is x^2+(3x)/(10)-1/10

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expand ((5x-1)(2x+1))/(10)

expand

\frac{( 5 x - 1 ) ( 2 x + 1 )}{10}

x^{2} + \frac{3 x}{10} - \frac{1}{10}

Solution steps

\frac{( 5 x - 1 ) ( 2 x + 1 )}{10}

Expand

(5 x - 1) (2 x + 1) : 10 x^{2} + 3 x - 1

= \frac{10 x ^{2} + 3 x - 1}{10}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 x ^{2} + 3 x - 1}{10} = \frac{10 x ^{2}}{10} + \frac{3 x}{10} - \frac{1}{10}

= \frac{10 x ^{2}}{10} + \frac{3 x}{10} - \frac{1}{10}

Divide the numbers:

\frac{10}{10} = 1

= x^{2} + \frac{3 x}{10} - \frac{1}{10}

\frac{3 ( 7 - 57 )}{20}

\frac{- 5 w + 18}{( w + 1 ) ( w - 3 )}

y^{'} (x) (x^{3} - cos (x))^{5}

((x + Δ x) - 1) (x - 1)

What is expand ((5x-1)(2x+1))/(10) ?
The solution to expand ((5x-1)(2x+1))/(10) is x^2+(3x)/(10)-1/10