What is expand (GA(GB-GC))/(1-GBHA) ?

The solution to expand (GA(GB-GC))/(1-GBHA) is (G^2AB-G^2AC)/(1-GABH)

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expand (GA(GB-GC))/(1-GBHA)

expand

\frac{G A ( GB - GC )}{1 - GB H A}

\frac{G ^{2} A B - G ^{2} A C}{1 - G A B H}

Solution steps

\frac{G A ( GB - GC )}{1 - GB H A}

Expand

G A (GB - GC) : G^{2} A B - G^{2} A C

= \frac{G ^{2} A B - G ^{2} A C}{1 - G A B H}

\frac{( x - 1 ) ( x + 2 )}{x + 6}

\frac{4}{3} π (x + 1)^{3}

\frac{5 - x}{( x - 9 ) ( x - 3 )}

\frac{x}{( x ^{2} + 3 x + 2 ) ^{2}}

- 1^{- 2} + 4

What is expand (GA(GB-GC))/(1-GBHA) ?
The solution to expand (GA(GB-GC))/(1-GBHA) is (G^2AB-G^2AC)/(1-GABH)