What are the solutions to the equation 0=(x-5)^2+2 ?

The solutions to the equation 0=(x-5)^2+2 are x=sqrt(2)i+5,x=-sqrt(2)i+5

Find the zeros of 0=(x-5)^2+2

The zeros of 0=(x-5)^2+2 are x=sqrt(2)i+5,x=-sqrt(2)i+5

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0 = (x - 5)^{2} + 2

x = 2 i + 5, x = - 2 i + 5

Solution steps

0 = (x - 5)^{2} + 2

Switch sides

(x - 5)^{2} + 2 = 0

Move

2

to the right side

(x - 5)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 2 : x = 2 i + 5

Solve

x - 5 = - - 2 : x = - 2 i + 5

The solutions to the quadratic equation are:

x = 2 i + 5, x = - 2 i + 5

- 16 \leq 5 x - 6 \leq 10

\frac{3}{5} x = \frac{23}{7}

125 c^{3} + 1

x + 4 \geq 5

i^{2001}

What are the solutions to the equation 0=(x-5)^2+2 ?
The solutions to the equation 0=(x-5)^2+2 are x=sqrt(2)i+5,x=-sqrt(2)i+5
Find the zeros of 0=(x-5)^2+2
The zeros of 0=(x-5)^2+2 are x=sqrt(2)i+5,x=-sqrt(2)i+5