What is expand ((2z+1)(4z-1))/2 ?

The solution to expand ((2z+1)(4z-1))/2 is 4z^2+z-1/2

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expand ((2z+1)(4z-1))/2

expand

\frac{( 2 z + 1 ) ( 4 z - 1 )}{2}

4 z^{2} + z - \frac{1}{2}

Solution steps

\frac{( 2 z + 1 ) ( 4 z - 1 )}{2}

Expand

(2 z + 1) (4 z - 1) : 8 z^{2} + 2 z - 1

= \frac{8 z ^{2} + 2 z - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 z ^{2} + 2 z - 1}{2} = \frac{8 z ^{2}}{2} + \frac{2 z}{2} - \frac{1}{2}

= \frac{8 z ^{2}}{2} + \frac{2 z}{2} - \frac{1}{2}

Divide the numbers:

\frac{8}{2} = 4

= 4 z^{2} + \frac{2 z}{2} - \frac{1}{2}

Divide the numbers:

\frac{2}{2} = 1

= 4 z^{2} + z - \frac{1}{2}

- 2 (x - 3 y = 6)

\frac{( x - 6 ) ( x - 5 )}{- 7 x - 2}

\frac{x}{1 + x ( y + z )}

4 (p - 5 = - 35)

\frac{1}{( 3 \cdot ( y ^{2} + 1 ) )}

What is expand ((2z+1)(4z-1))/2 ?
The solution to expand ((2z+1)(4z-1))/2 is 4z^2+z-1/2