What is expand (x+5)\circ (x-3) ?

The solution to expand (x+5)\circ (x-3) is \circ x^2+2\circ x-15\circ

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+5)\circ (x-3)

expand

(x + 5) \circ (x - 3)

\circ x^{2} + 2 \circ x - 15 \circ

Solution steps

(x + 5) \circ (x - 3)

= \circ (x + 5) (x - 3)

Expand

(x + 5) (x - 3) : x^{2} + 2 x - 15

= \circ (x^{2} + 2 x - 15)

Expand

\circ (x^{2} + 2 x - 15) : \circ x^{2} + 2 \circ x - 15 \circ

= \circ x^{2} + 2 \circ x - 15 \circ

(5 x - 2 y) y^{'} (x) + x - y

20 π (x + 4)^{2}

\frac{2 ( 1 + y )}{1 + x}

\frac{( x + y )}{( 1 + a ) ^{b}}

\frac{3 x ^{2}}{( 1 + 2 x ) ^{2}}

What is expand (x+5)\circ (x-3) ?
The solution to expand (x+5)\circ (x-3) is \circ x^2+2\circ x-15\circ