What is expand ((x-3)(x+1))/((x-1)^2) ?

The solution to expand ((x-3)(x+1))/((x-1)^2) is (x^2-2x-3)/(x^2-2x+1)

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expand ((x-3)(x+1))/((x-1)^2)

expand

\frac{( x - 3 ) ( x + 1 )}{( x - 1 ) ^{2}}

\frac{x ^{2} - 2 x - 3}{x ^{2} - 2 x + 1}

Solution steps

\frac{( x - 3 ) ( x + 1 )}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{( x - 3 ) ( x + 1 )}{x ^{2} - 2 x + 1}

Expand

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \frac{x ^{2} - 2 x - 3}{x ^{2} - 2 x + 1}

cos (θ) (- 3, - 5)

5 (5 x + 7 x = - 2)

(e^{- x} - 1) (e^{x})

A (1, - 5) y B (- 2, 4)

(- x + 3 y, x + 2 y) y (7, 8)

What is expand ((x-3)(x+1))/((x-1)^2) ?
The solution to expand ((x-3)(x+1))/((x-1)^2) is (x^2-2x-3)/(x^2-2x+1)