What is expand ((2x-1)(x+2)(x-3))/2 ?

The solution to expand ((2x-1)(x+2)(x-3))/2 is x^3-(3x^2)/2-(11x)/2+3

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expand ((2x-1)(x+2)(x-3))/2

expand

\frac{( 2 x - 1 ) ( x + 2 ) ( x - 3 )}{2}

x^{3} - \frac{3 x ^{2}}{2} - \frac{11 x}{2} + 3

Solution steps

\frac{( 2 x - 1 ) ( x + 2 ) ( x - 3 )}{2}

Expand

(2 x - 1) (x + 2) (x - 3) : 2 x^{3} - 3 x^{2} - 11 x + 6

= \frac{2 x ^{3} - 3 x ^{2} - 11 x + 6}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{3} - 3 x ^{2} - 11 x + 6}{2} = \frac{2 x ^{3}}{2} - \frac{3 x ^{2}}{2} - \frac{11 x}{2} + \frac{6}{2}

= \frac{2 x ^{3}}{2} - \frac{3 x ^{2}}{2} - \frac{11 x}{2} + \frac{6}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{3} - \frac{3 x ^{2}}{2} - \frac{11 x}{2} + \frac{6}{2}

Divide the numbers:

\frac{6}{2} = 3

= x^{3} - \frac{3 x ^{2}}{2} - \frac{11 x}{2} + 3

3 tan (2) (x - π)

- 300 (t + 2) e^{- \frac{t}{2}} + C

(2 + y) d x - (3 - x) d y

(- x^{2} + 3 x + 6) + (3 - x) d x

4 (14 x - 4 x ln (2)) d x

What is expand ((2x-1)(x+2)(x-3))/2 ?
The solution to expand ((2x-1)(x+2)(x-3))/2 is x^3-(3x^2)/2-(11x)/2+3