What is expand e^{3x}(-2e^{-3x}+C) ?

The solution to expand e^{3x}(-2e^{-3x}+C) is -2+e^{3x}C

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expand e^{3x}(-2e^{-3x}+C)

expand

e^{3 x} (- 2 e^{- 3 x} + C)

- 2 + e^{3 x} C

Solution steps

e^{3 x} (- 2 e^{- 3 x} + C)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{3 x}, b = - 2 e^{- 3 x}, c = C

= e^{3 x} (- 2 e^{- 3 x}) + e^{3 x} C

Apply minus-plus rules

+ (- a) = - a

= - 2 e^{3 x} e^{- 3 x} + e^{3 x} C

2 e^{3 x} e^{- 3 x} = 2

= - 2 + e^{3 x} C

\frac{( a + m ) ( a + n )}{2}

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(x - 3 y - 5 z = 0) (6, 4, 9)

\frac{z ( z + 5 )}{( z + 2 ) ( z + 3 )}

What is expand e^{3x}(-2e^{-3x}+C) ?
The solution to expand e^{3x}(-2e^{-3x}+C) is -2+e^{3x}C