What is expand (2x^2-5x+1)\circ (2x-3) ?

The solution to expand (2x^2-5x+1)\circ (2x-3) is 4\circ x^3-16\circ x^2+17\circ x-3\circ

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expand (2x^2-5x+1)\circ (2x-3)

expand

(2 x^{2} - 5 x + 1) \circ (2 x - 3)

4 \circ x^{3} - 16 \circ x^{2} + 17 \circ x - 3 \circ

Solution steps

(2 x^{2} - 5 x + 1) \circ (2 x - 3)

= \circ (2 x^{2} - 5 x + 1) (2 x - 3)

Expand

(2 x^{2} - 5 x + 1) (2 x - 3) : 4 x^{3} - 16 x^{2} + 17 x - 3

= \circ (4 x^{3} - 16 x^{2} + 17 x - 3)

Expand

\circ (4 x^{3} - 16 x^{2} + 17 x - 3) : 4 \circ x^{3} - 16 \circ x^{2} + 17 \circ x - 3 \circ

= 4 \circ x^{3} - 16 \circ x^{2} + 17 \circ x - 3 \circ

- 2 \cdot (1 - ln (x))

36 (1 - \frac{π}{4})

(x + 20 x tan (1 0^{\circ}))^{2}

\frac{x}{( 12000 - x ) ^{2}}

40 + 6 (6 - 2)

What is expand (2x^2-5x+1)\circ (2x-3) ?
The solution to expand (2x^2-5x+1)\circ (2x-3) is 4\circ x^3-16\circ x^2+17\circ x-3\circ