What is expand ((3-2x^2)^2)/2 ?

The solution to expand ((3-2x^2)^2)/2 is 2x^4-6x^2+9/2

Popular >

expand ((3-2x^2)^2)/2

expand

\frac{( 3 - 2 x ^{2} ) ^{2}}{2}

2 x^{4} - 6 x^{2} + \frac{9}{2}

Solution steps

\frac{( 3 - 2 x ^{2} ) ^{2}}{2}

(3 - 2 x^{2})^{2} = 9 - 12 x^{2} + 4 x^{4}

= \frac{9 - 12 x ^{2} + 4 x ^{4}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 12 x ^{2} + 4 x ^{4}}{2} = \frac{9}{2} - \frac{12 x ^{2}}{2} + \frac{4 x ^{4}}{2}

= \frac{9}{2} - \frac{12 x ^{2}}{2} + \frac{4 x ^{4}}{2}

Divide the numbers:

\frac{12}{2} = 6

= \frac{9}{2} - 6 x^{2} + \frac{4 x ^{4}}{2}

Divide the numbers:

\frac{4}{2} = 2

= \frac{9}{2} - 6 x^{2} + 2 x^{4}

Rewrite in standard form

= 2 x^{4} - 6 x^{2} + \frac{9}{2}

\frac{2 R}{( R ^{2} + 9 ) ^{2}}

\frac{3 x + 2}{x ( x ^{2} - 9 )}

ln (y^{2} + z^{2})

\frac{( y ^{6} - 4 ) ^{2}}{16 y ^{6}}

\frac{x ^{3} ( 3 x + 8 )}{12}

What is expand ((3-2x^2)^2)/2 ?
The solution to expand ((3-2x^2)^2)/2 is 2x^4-6x^2+9/2