What is expand (2x^2+x+8)/((2x-1)(x+3)) ?

The solution to expand (2x^2+x+8)/((2x-1)(x+3)) is (2x^2+x+8)/(2x^2+5x-3)

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expand (2x^2+x+8)/((2x-1)(x+3))

expand

\frac{2 x ^{2} + x + 8}{( 2 x - 1 ) ( x + 3 )}

\frac{2 x ^{2} + x + 8}{2 x ^{2} + 5 x - 3}

Solution steps

\frac{2 x ^{2} + x + 8}{( 2 x - 1 ) ( x + 3 )}

Expand

(2 x - 1) (x + 3) : 2 x^{2} + 5 x - 3

= \frac{2 x ^{2} + x + 8}{2 x ^{2} + 5 x - 3}

\frac{( ( x - 4 ) ^{4} )}{4}

(2 + \frac{5}{8} x)^{8}

(\frac{( 8 - b )}{3})^{2}

(\frac{x - y}{2} - 6 + 120 = 0) (2)

\frac{b}{( s ^{2} ( s + a ) )}

What is expand (2x^2+x+8)/((2x-1)(x+3)) ?
The solution to expand (2x^2+x+8)/((2x-1)(x+3)) is (2x^2+x+8)/(2x^2+5x-3)