What is expand (f\circ g)x(3x-4)+2 ?

The solution to expand (f\circ g)x(3x-4)+2 is 3\circ fgx^2-4\circ fgx+2

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expand (f\circ g)x(3x-4)+2

expand

(f \circ g) x (3 x - 4) + 2

3 \circ f g x^{2} - 4 \circ f gx + 2

Solution steps

(f \circ g) x (3 x - 4) + 2

= x (\circ f g) (3 x - 4) + 2

Expand

(f \circ g) x (3 x - 4) : 3 \circ f g x^{2} - 4 \circ f gx

= 3 \circ f g x^{2} - 4 \circ f gx + 2

(2 x + 3) e^{5 x}

(16 x^{2} + 40 x + 25) ln (x)

\frac{1}{( x - 2 ) ( x + 3 )}

\frac{x ^{3}}{( 3 x - 2 ) ^{2}}

\frac{( w + 2 ) ( w + 7 )}{( w + 5 ) ( w - 3 )}

What is expand (f\circ g)x(3x-4)+2 ?
The solution to expand (f\circ g)x(3x-4)+2 is 3\circ fgx^2-4\circ fgx+2