What is expand (2(ab+ac+bc))/(abc) ?

The solution to expand (2(ab+ac+bc))/(abc) is 2/c+2/b+2/a

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expand (2(ab+ac+bc))/(abc)

expand

\frac{2 ( ab + a c + b c )}{ab c}

\frac{2}{c} + \frac{2}{b} + \frac{2}{a}

Solution steps

\frac{2 ( ab + a c + b c )}{ab c}

Expand

2 (ab + a c + b c) : 2 ab + 2 a c + 2 b c

= \frac{2 ab + 2 a c + 2 b c}{ab c}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 ab + 2 a c + 2 b c}{ab c} = \frac{2 ab}{ab c} + \frac{2 a c}{ab c} + \frac{2 b c}{ab c}

= \frac{2 ab}{ab c} + \frac{2 a c}{ab c} + \frac{2 b c}{ab c}

Cancel

\frac{2 ab}{ab c} : \frac{2}{c}

= \frac{2}{c} + \frac{2 a c}{ab c} + \frac{2 b c}{ab c}

Cancel

\frac{2 a c}{ab c} : \frac{2}{b}

= \frac{2}{c} + \frac{2}{b} + \frac{2 b c}{ab c}

Cancel

\frac{2 b c}{ab c} : \frac{2}{a}

= \frac{2}{c} + \frac{2}{b} + \frac{2}{a}

\frac{( 2 x ) !}{x ! ^{2} ( x + 1 )}

4 x 4 - 3 x 2 + 2 x

x (a + b + x = 0)

(20 x = 0,) (90 x - 4 = 0,) (45 x - y = 0)

π (n - 3)^{2}

What is expand (2(ab+ac+bc))/(abc) ?
The solution to expand (2(ab+ac+bc))/(abc) is 2/c+2/b+2/a