What is expand (n^{n^3})/((n-1)^2) ?

The solution to expand (n^{n^3})/((n-1)^2) is (n^{n^3})/(n^2-2n+1)

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expand (n^{n^3})/((n-1)^2)

expand

\frac{n ^{n^{3}}}{( n - 1 ) ^{2}}

\frac{n ^{n^{3}}}{n ^{2} - 2 n + 1}

Solution steps

\frac{n ^{n^{3}}}{( n - 1 ) ^{2}}

(n - 1)^{2} = n^{2} - 2 n + 1

= \frac{n ^{n^{3}}}{n ^{2} - 2 n + 1}

π (a y - \frac{y ^{2}}{2})

7 (- 4 x + 9 y = 28)

1.67 (1.67 q + 5 = - 2.5 q + 42.5) + 5

(4 m + 3) (- 4 m - 5)^{\circ}

(x - y) d x - (x + 3 y) d y

What is expand (n^{n^3})/((n-1)^2) ?
The solution to expand (n^{n^3})/((n-1)^2) is (n^{n^3})/(n^2-2n+1)