What is expand ((n+2)(n+1)(n+3))/(n^3) ?

The solution to expand ((n+2)(n+1)(n+3))/(n^3) is 1+6/n+(11)/(n^2)+6/(n^3)

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expand ((n+2)(n+1)(n+3))/(n^3)

expand

\frac{( n + 2 ) ( n + 1 ) ( n + 3 )}{n ^{3}}

1 + \frac{6}{n} + \frac{11}{n ^{2}} + \frac{6}{n ^{3}}

Solution steps

\frac{( n + 2 ) ( n + 1 ) ( n + 3 )}{n ^{3}}

Expand

(n + 2) (n + 1) (n + 3) : n^{3} + 6 n^{2} + 11 n + 6

= \frac{n ^{3} + 6 n ^{2} + 11 n + 6}{n ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} + 6 n ^{2} + 11 n + 6}{n ^{3}} = \frac{n ^{3}}{n ^{3}} + \frac{6 n ^{2}}{n ^{3}} + \frac{11 n}{n ^{3}} + \frac{6}{n ^{3}}

= \frac{n ^{3}}{n ^{3}} + \frac{6 n ^{2}}{n ^{3}} + \frac{11 n}{n ^{3}} + \frac{6}{n ^{3}}

Apply rule

\frac{a}{a} = 1

\frac{n ^{3}}{n ^{3}} = 1

= 1 + \frac{6 n ^{2}}{n ^{3}} + \frac{11 n}{n ^{3}} + \frac{6}{n ^{3}}

Cancel

\frac{6 n ^{2}}{n ^{3}} : \frac{6}{n}

= 1 + \frac{6}{n} + \frac{11 n}{n ^{3}} + \frac{6}{n ^{3}}

Cancel

\frac{11 n}{n ^{3}} : \frac{11}{n ^{2}}

= 1 + \frac{6}{n} + \frac{11}{n ^{2}} + \frac{6}{n ^{3}}

A (1, 2) B (3, - 1)

- (x^{2} y - y^{3}) d y

2 (\frac{1}{2} x + 13 = 9)

(x + Δ x)^{3} + 2 (x + Δ x)

\frac{x + 2 - x ^{2}}{x ( x + 2 )}

What is expand ((n+2)(n+1)(n+3))/(n^3) ?
The solution to expand ((n+2)(n+1)(n+3))/(n^3) is 1+6/n+(11)/(n^2)+6/(n^3)