What is expand 2x^2+8x-(x^2+6x-9=0) ?

The solution to expand 2x^2+8x-(x^2+6x-9=0) is x^2+2x+9=0

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expand 2x^2+8x-(x^2+6x-9=0)

expand

2 x^{2} + 8 x - (x^{2} + 6 x - 9 = 0)

x^{2} + 2 x + 9 = 0

Solution steps

2 x^{2} + 8 x - (x^{2} + 6 x - 9 = 0)

= 2 x^{2} + 8 x - (x^{2} + 6 x - 9 \cdot 0 =)

- (x^{2} + 6 x - 9 = 0) : - x^{2} - 6 x + 9 = 0

2 x^{2} + 8 x - x^{2} - 6 x + 9 = 0

Expand

2 x^{2} + 8 x - x^{2} - 6 x + 9 : x^{2} + 2 x + 9

x^{2} + 2 x + 9 = 0

2 e^{t} F (s + 1)

- 4 (3 e - 4)

\frac{( x - 1 )}{( x + 5 ) ^{2}}

\frac{s - r + 1}{( r + 1 ) ^{2}}

(2 x^{2} - x) e^{x} (2 x - 1)

What is expand 2x^2+8x-(x^2+6x-9=0) ?
The solution to expand 2x^2+8x-(x^2+6x-9=0) is x^2+2x+9=0