What is expand ((6x-1)^3)/(18) ?

The solution to expand ((6x-1)^3)/(18) is 12x^3-6x^2+x-1/18

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expand ((6x-1)^3)/(18)

expand

\frac{( 6 x - 1 ) ^{3}}{18}

12 x^{3} - 6 x^{2} + x - \frac{1}{18}

Solution steps

\frac{( 6 x - 1 ) ^{3}}{18}

(6 x - 1)^{3} = 216 x^{3} - 108 x^{2} + 18 x - 1

= \frac{216 x ^{3} - 108 x ^{2} + 18 x - 1}{18}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{216 x ^{3} - 108 x ^{2} + 18 x - 1}{18} = \frac{216 x ^{3}}{18} - \frac{108 x ^{2}}{18} + \frac{18 x}{18} - \frac{1}{18}

= \frac{216 x ^{3}}{18} - \frac{108 x ^{2}}{18} + \frac{18 x}{18} - \frac{1}{18}

Divide the numbers:

\frac{216}{18} = 12

= 12 x^{3} - \frac{108 x ^{2}}{18} + \frac{18 x}{18} - \frac{1}{18}

Divide the numbers:

\frac{108}{18} = 6

= 12 x^{3} - 6 x^{2} + \frac{18 x}{18} - \frac{1}{18}

Divide the numbers:

\frac{18}{18} = 1

= 12 x^{3} - 6 x^{2} + x - \frac{1}{18}

(- 3, - 1) P (- 6 - 3)

ln (3) (x - 5)

- \frac{7 ( 5 - 2 x )}{25 - 4 x}

\frac{( 5 x + 3 ) ( 5 x - 3 )}{25}

(x + δ x)^{2} - 4

What is expand ((6x-1)^3)/(18) ?
The solution to expand ((6x-1)^3)/(18) is 12x^3-6x^2+x-1/18