What is expand-(3n^2(n+1)^2)/2 ?

The solution to expand-(3n^2(n+1)^2)/2 is -(3n^4)/2-3n^3-(3n^2)/2

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expand-(3n^2(n+1)^2)/2

expand

- \frac{3 n ^{2} ( n + 1 ) ^{2}}{2}

- \frac{3 n ^{4}}{2} - 3 n^{3} - \frac{3 n ^{2}}{2}

Solution steps

- \frac{3 n ^{2} ( n + 1 ) ^{2}}{2}

(n + 1)^{2} = n^{2} + 2 n + 1

= - \frac{3 n ^{2} ( n ^{2} + 2 n + 1 )}{2}

Expand

3 n^{2} (n^{2} + 2 n + 1) : 3 n^{4} + 6 n^{3} + 3 n^{2}

= - \frac{3 n ^{4} + 6 n ^{3} + 3 n ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 n ^{4} + 6 n ^{3} + 3 n ^{2}}{2} = - (\frac{3 n ^{4}}{2}) - (\frac{6 n ^{3}}{2}) - (\frac{3 n ^{2}}{2})

= - (\frac{3 n ^{4}}{2}) - (\frac{6 n ^{3}}{2}) - (\frac{3 n ^{2}}{2})

Remove parentheses:

(a) = a

= - \frac{3 n ^{4}}{2} - \frac{6 n ^{3}}{2} - \frac{3 n ^{2}}{2}

Divide the numbers:

\frac{6}{2} = 3

= - \frac{3 n ^{4}}{2} - 3 n^{3} - \frac{3 n ^{2}}{2}

π (x^{2} + 6 x + 3)^{2}

\frac{( x + 2 )}{2} + (x + 2)

(5 x + 6 y = 20,) (8 x - 6 y = - 46)

\frac{5 ( x ^{2} - 3 )}{x - 1}

\frac{- 2 s + 3}{s ( s - 1 )}

What is expand-(3n^2(n+1)^2)/2 ?
The solution to expand-(3n^2(n+1)^2)/2 is -(3n^4)/2-3n^3-(3n^2)/2