What is expand (1-6x)/(x^2(2x-1)) ?

The solution to expand (1-6x)/(x^2(2x-1)) is (1-6x)/(2x^3-x^2)

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expand (1-6x)/(x^2(2x-1))

expand

\frac{1 - 6 x}{x ^{2} ( 2 x - 1 )}

\frac{1 - 6 x}{2 x ^{3} - x ^{2}}

Solution steps

\frac{1 - 6 x}{x ^{2} ( 2 x - 1 )}

Expand

x^{2} (2 x - 1) : 2 x^{3} - x^{2}

= \frac{1 - 6 x}{2 x ^{3} - x ^{2}}

30 (4 x^{5} + x)^{29} (20 x^{4} + 1)

\frac{16}{s ( s + 1 ) ( s + 5 )}

\frac{t ( s - 1 )}{s ( s ^{2} - s - 2 )}

(x + x u^{2} - 1) x d u

(1 - 4 1)

What is expand (1-6x)/(x^2(2x-1)) ?
The solution to expand (1-6x)/(x^2(2x-1)) is (1-6x)/(2x^3-x^2)