What is expand (dx)/((x^2+3)(x^2-3)) ?

The solution to expand (dx)/((x^2+3)(x^2-3)) is (dx)/(x^4-9)

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expand (dx)/((x^2+3)(x^2-3))

expand

\frac{d x}{( x ^{2} + 3 ) ( x ^{2} - 3 )}

\frac{d x}{x ^{4} - 9}

Solution steps

\frac{d x}{( x ^{2} + 3 ) ( x ^{2} - 3 )}

Expand

(x^{2} + 3) (x^{2} - 3) : x^{4} - 9

= \frac{d x}{x ^{4} - 9}

y + 4 (y - 1 = 9 - 2 (y + 3))

\frac{( x ^{2} + 8 ) ^{2}}{x ^{5}}

- \frac{67}{100 ( p - 126 )}

- 3 + 3 \frac{3}{4}

x - (1 - \frac{x ^{2}}{3} x + x = 0)

What is expand (dx)/((x^2+3)(x^2-3)) ?
The solution to expand (dx)/((x^2+3)(x^2-3)) is (dx)/(x^4-9)