What is expand-(x^2(9-6x+x^2))/(18) ?

The solution to expand-(x^2(9-6x+x^2))/(18) is -(x^4}{18}+\frac{x^3)/3-(x^2)/2

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expand-(x^2(9-6x+x^2))/(18)

expand

- \frac{x ^{2} ( 9 - 6 x + x ^{2} )}{18}

- \frac{x ^{4}}{18} + \frac{x ^{3}}{3} - \frac{x ^{2}}{2}

Solution steps

- \frac{x ^{2} ( 9 - 6 x + x ^{2} )}{18}

Expand

x^{2} (9 - 6 x + x^{2}) : 9 x^{2} - 6 x^{3} + x^{4}

= - \frac{x ^{4} - 6 x ^{3} + 9 x ^{2}}{18}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 6 x ^{3} + x ^{4}}{18} = - (\frac{9 x ^{2}}{18}) - (- \frac{6 x ^{3}}{18}) - (\frac{x ^{4}}{18})

= - (\frac{9 x ^{2}}{18}) - (- \frac{6 x ^{3}}{18}) - (\frac{x ^{4}}{18})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{9 x ^{2}}{18} + \frac{6 x ^{3}}{18} - \frac{x ^{4}}{18}

Cancel

\frac{9 x ^{2}}{18} : \frac{x ^{2}}{2}

= - \frac{x ^{2}}{2} + \frac{6 x ^{3}}{18} - \frac{x ^{4}}{18}

Cancel

\frac{6 x ^{3}}{18} : \frac{x ^{3}}{3}

= - \frac{x ^{2}}{2} + \frac{x ^{3}}{3} - \frac{x ^{4}}{18}

Rewrite in standard form

= - \frac{x ^{4}}{18} + \frac{x ^{3}}{3} - \frac{x ^{2}}{2}

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What is expand-(x^2(9-6x+x^2))/(18) ?
The solution to expand-(x^2(9-6x+x^2))/(18) is -(x^4}{18}+\frac{x^3)/3-(x^2)/2