What is factor t^2+12t-13 ?

The solution to factor t^2+12t-13 is (t-1)(t+13)

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factor t^2+12t-13

factor

t^{2} + 12 t - 13

(t - 1) (t + 13)

Solution steps

t^{2} + 12 t - 13

Break the expression into groups

= (t^{2} - t) + (13 t - 13)

Factor out

t

from

t^{2} - t : t (t - 1)

Factor out

13

from

13 t - 13 : 13 (t - 1)

= t (t - 1) + 13 (t - 1)

Factor out common term

t - 1

= (t - 1) (t + 13)

2 x^{2} + 7 = 0

z = 10 e^{- i \frac{4 π}{9}}

\frac{5}{12} - \frac{1}{12}

x^{2} \leq 3 x + 40

s = 180 (4 - 2)