What is expand possible 1/3 (3j+6) ?

The solution to expand possible 1/3 (3j+6) is i(2elpos^2b+eljpos^2b)

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expand possible 1/3 (3j+6)

expand

p oss ib l e \frac{1}{3} (3 j + 6)

i (2 e lp o s^{2} b + e l j p o s^{2} b)

Solution steps

p oss ib l e \frac{1}{3} (3 j + 6)

= i e \frac{1}{3} lp oss b (3 j + 6)

Apply the distributive law:

a (b + c) = ab + a c

a = p oss ib l e \frac{1}{3}, b = 3 j, c = 6

= p oss ib l e \frac{1}{3} \cdot 3 j + p oss ib l e \frac{1}{3} \cdot 6

= 3 i e \frac{1}{3} l j p oss b + 6 i e \frac{1}{3} lp oss b

Simplify

3 i e \frac{1}{3} l j p oss b + 6 i e \frac{1}{3} lp oss b : i (2 e lp o s^{2} b + e l j p o s^{2} b)

= i (2 e lp o s^{2} b + e l j p o s^{2} b)

\frac{( ( 4 m - 4 ) ^{2} )}{m - 1}

5 cos (2 (x + \frac{π}{3}))

(2 x + y) (cos (t)) + (2 y + x) (e^{t})

\frac{5 ( x - 3 ) ^{5}}{16}

\frac{( x + 1 ) ( - x + 10 )}{2}

What is expand possible 1/3 (3j+6) ?
The solution to expand possible 1/3 (3j+6) is i(2elpos^2b+eljpos^2b)